A) 0.4
B) 0.8
C) 0.1
D) 0.2
Correct Answer: C
Solution :
[c] V.P. of solution at \[t{}^\circ C=760\text{ }mm\] [at b.p., V.P. of solution =atompheric pressure] Thus \[=P_{A}^{{}^\circ }.{{x}_{A}}+P_{B}^{{}^\circ }.{{x}_{B}}\] or \[P=P_{A}^{{}^\circ }.{{X}_{A}}+P_{B}^{{}^\circ }.(1-{{x}_{A}})\,[\therefore {{x}_{A}}+{{x}_{B}}=1]\] or \[760=400{{X}_{A}}+800(1-{{X}_{A}})\] \[\left[ \therefore P=760\text{ }mm\,of\,Hg \right]\] or \[-800+760=-400{{x}_{A}}\] or \[-40=-400{{x}_{A}}\] or \[{{x}_{A}}=\frac{40}{400}=0.1\] Thus mole fraction of in solution is 0.1You need to login to perform this action.
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