A) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{3}}]Cl\]
B) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}\]
C) \[[Pt{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{3}}\]
D) \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\]
Correct Answer: B
Solution :
[b] \[\Delta {{T}_{f}}=i.{{K}_{f}}.m;\text{ }0.0054=i\times 1.8\times 0.001\] \[i=3\] so it is \[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}.\]You need to login to perform this action.
You will be redirected in
3 sec