A) 34.2 g
B) 342 g
C) 7.2 g
D) 72 g
Correct Answer: D
Solution :
[d] \[(100+\Delta {{T}_{b}})-(0-\Delta {{T}_{f}})=105\] \[\Delta {{T}_{b}}+\Delta {{T}_{f}}=5\] \[m\left( {{K}_{b}}+{{K}_{f}} \right)=5\] \[m=\frac{5}{2.37}\] i.e., \[\frac{5}{2.37}\] moles in 1000 g water (or) \[\frac{5}{2.37\times 10}\] moles in 100 g water \[\therefore \] Wt. of sucrose\[=\frac{5}{2.37\times 10}\times 342=72g\]You need to login to perform this action.
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