A) 0.52
B) 1.04
C) 1.34
D) 0.052
Correct Answer: D
Solution :
[d] \[\Delta {{T}_{f}}=i.{{K}_{f}}.m;\Delta {{T}_{b}}=i.{{K}_{b}}.m\] \[\frac{\Delta {{T}_{f}}}{\Delta {{T}_{b}}}=\frac{{{K}_{f}}}{{{K}_{b}}}\] \[\Delta {{T}_{f}}=0-\left( -0.186{}^\circ C \right)=0.186{}^\circ C\] \[\frac{0.186}{\Delta {{T}_{b}}}=\frac{1.86}{0.52}\Rightarrow \Delta {{T}_{b}}=\frac{0.52\times 0.186}{1.86}=0.052\]You need to login to perform this action.
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