A) 1
B) 3
C) 4
D) 8
Correct Answer: C
Solution :
[c] Molecular mass of phosphorous \[=\frac{1000\times {{K}_{f}}\times {{W}_{solute}}}{\Delta {{T}_{f}}\times {{W}_{benzene}}}\] \[=\frac{1000\times 5.12\times 2.48}{1.02\times 100}=124.5={{(P)}_{x}}\] Or , \[x=\frac{124.5}{31}=4\]You need to login to perform this action.
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