A) \[6.023\times {{10}^{23}}\]
B) \[12.04\times {{10}^{23}}\]
C) \[18.06\times {{10}^{23}}\]
D) \[24.08\times {{10}^{22}}\]
Correct Answer: D
Solution :
[d] At S.T.P. 22.4 litre of gas contains \[6.023\times {{10}^{23}}\]molecules \[\therefore \] molecules in 8.96 litre of gas \[=\frac{6.023\times {{10}^{23}}\times 8.96}{22.4}=24.08\times {{10}^{22}}\]
You need to login to perform this action.
You will be redirected in
3 sec
