A) 6.5 g
B) 0.65 g
C) 65 g
D) 0.065g
Correct Answer: B
Solution :
[b] \[Zn+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}ZnS{{O}_{4}}+{{H}_{2}}\] 65 g Zn gives 1 mole of \[{{H}_{2}}=22400\text{ }mL\] of \[{{H}_{2}}=224\text{ }mL\] of \[{{H}_{2}}\]will be obtained from 0.65 g Zn.You need to login to perform this action.
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