A) 2.60 m
B) 2.18 m
C) 2.79 m
D) 3.00 m
Correct Answer: C
Solution :
[c] The relation between molarity (M) and molality (m) is \[d=M\left( \frac{1}{m}+\frac{{{M}_{2}}}{1000} \right).\] |
\[{{M}_{2}}\]= Mol. mass of solute |
On putting value \[1.252=3\left( \frac{1}{m}+\frac{58.8}{1000} \right)\] on solving m= 2.79 |
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