A) 17.8 M
B) 12.0.M
C) 10.5 M
D) 15.7 M
Correct Answer: A
Solution :
| [a] 95% \[{{H}_{2}}S{{O}_{4}}\] by weight means 100g\[{{H}_{2}}S{{O}_{4}}\] solution contains 95g \[{{H}_{2}}S{{O}_{4}}\] by mass. Molar mass of\[{{H}_{2}}S{{O}_{4}}~=98g\text{ }mo{{l}^{-1}}\] |
| Moles in \[95g=\frac{95}{98}=0.969\] mole |
| Volume of \[100g\,{{H}_{2}}S{{O}_{4}}\] \[=\frac{mass}{density}=\frac{100g}{1.834gc{{m}^{-3}}}\] |
| \[=54.52c{{m}^{3}}=54.52\times {{10}^{-3}}L\] |
| \[\text{Molarity}=\frac{\text{Moles of}\,\,\text{solute}}{\text{Voime of solute in L}}\] |
| \[=\frac{0.969}{54.52\times {{10}^{-3}}}=17.8M\] |
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