| 9 moles of "D" and 14 moles of E are allowed to react in a closed vessel according to given reactions. Calculate number of moles of B formed in the end of reaction, if 4 moles of G are present in reaction vessel. (Percentage yield of reaction is mentioned in the reaction) |
| Step-1 \[3D+4E\xrightarrow{80%}~5C+A\] |
| Step-2 \[3C+5G\,\xrightarrow{50%}6B+F\] |
A) 2.4
B) 30
C) 4.8
D) 1
Correct Answer: A
Solution :
[a] \[3D+4E\xrightarrow{80\,percent}5C+A\] 9 mole 14 mole \[\frac{5}{3}\times 9\times 0.8=12\] mole \[\underset{12\,mole}{\mathop{3C}}\,~+\underset{4\,\,mole}{\mathop{5G}}\,\xrightarrow{50\,percent}6B\,\,+\,\,F\] Limiting Reagent is G \[\therefore \] Moles of B formed \[=\frac{6}{5}\times 4\times 0.5=2.4\]
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