A) \[1.568\times {{10}^{3}}\]
B) \[1.568\times {{10}^{4}}\]
C) 15.68
D) \[3.136\times {{10}^{4}}\]
Correct Answer: B
Solution :
[b] 0.5% by weight means of Mol. wt. is 100 then mass of Se is 0.5. If at least one atom of Se is present in the molecule then \[M.Wt=\frac{100}{0.5}\times 78.4=1.568\times {{10}^{4}}\]You need to login to perform this action.
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