A) 157.7mL
B) 15.77 mL
C) 147.7 mL
D) 14.77 mL
Correct Answer: A
Solution :
[a] \[\underset{x}{\mathop{N{{a}_{2}}C{{O}_{3}}}}\,\] \[\underset{(1-x)}{\mathop{NaHC{{O}_{3}}}}\,\] \[\frac{x}{106}=\frac{1-x}{84}\] given (moles are equal) \[x=0.557\] \[\frac{0.557}{53}+\frac{0.443}{84}=\frac{V\times 0.1}{1000}\] \[V=157.7\text{ }mL\]You need to login to perform this action.
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