A) 0.1 N and the solution is basic
B) 0.1 N and the solution is acidic
C) 0.05 N and the solution is basic
D) 0.05 N and the solution is acidic
Correct Answer: C
Solution :
[c] Normality \[=\frac{{{N}_{1}}{{V}_{1}}-{{N}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}=\frac{0.2\times 100-0.1\times 100}{100+100}\] \[=\frac{10}{100}=0.05N\,NaOH\]You need to login to perform this action.
You will be redirected in
3 sec