A) 4 mL
B) 20 mL
C) 2 mL
D) 40 mL
Correct Answer: D
Solution :
[d] Normality of oxalic acid solution \[=\frac{6.3\times 1000}{63\times 250}=0.4N\] Now from \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.4\times 10=0.1\times {{V}_{2}}\] \[{{V}_{2}}=40mL\]
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