A) 95%
B) 85%
C) 75%
D) 65%
Correct Answer: A
Solution :
[a] The reaction that takes place is |
\[NaCl+AgN{{O}_{3}}\xrightarrow{{}}AgCl\downarrow +NaN{{O}_{3}}\] |
\[\therefore \] 143.5 g of \[AgCl\] is produced from 58.5 g |
\[\therefore \]14 g of \[AgCl\] will be produced from \[\frac{58.5\times 14}{143.5}=5.70g\,NaCl\] |
This is the amount of NaCl in common salt; % purity \[=\frac{570}{6}\times 100=95%\]% |
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