A) 4.5 g
B) 5.6 g
C) 8.09 g
D) 6.6 g
Correct Answer: C
Solution :
[c] \[\underset{78g}{\mathop{{{C}_{6}}{{H}_{6}}}}\,+HN{{O}_{3}}\to \underset{123g}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,+{{H}_{2}}O\] Now since 78g of benzene on nitration give = 123g nitrobenzene hence 5g of benzene on nitration give \[=\frac{123}{78}\times 5=7.88g\] nearest answer is [c] i.e. theoritical yield =7.88gYou need to login to perform this action.
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