A) 16.0
B) 41.2
C) 82.4
D) 156.0
Correct Answer: C
Solution :
[c] Let the alcohol be ROH and x its molecular weight |
\[\underset{xg}{\mathop{ROH}}\,+C{{H}_{3}}MgI\to \underset{16g}{\mathop{C{{H}_{4}}}}\,+ROMgI\] |
\[\frac{4.12}{1000}g\] of alcohol will produce \[\frac{16}{x}\times \frac{4.12}{1000}g\]of methane |
Methane actually obtained is = \[\frac{16\times 1.12}{22400}g\] |
\[\therefore \frac{16\times 4.12}{x\times 1000}=\frac{16\times 1.12}{22400}=x=82.4\] |
You need to login to perform this action.
You will be redirected in
3 sec