A) \[MC{{l}_{3}}\]
B) \[MC{{l}_{2}}\]
C) \[MC{{l}_{4}}\]
D) \[MC{{l}_{5}}\]
Correct Answer: C
Solution :
| [c] 74.75% of chlorine means 74.75g chlorine is present in \[100g\] of metal chloride. |
| Weight of metal = \[100g-74.75g\]\[=25.25g\] |
| Equivalent weight \[=\frac{weight\text{ }of\text{ }metal}{weight\text{ }of\text{ }chlorine}\times 35.5\]\[=\frac{25.25}{74.25}\times 35.5=12\] |
| Valency of metal \[=\frac{2\times V.D.}{Equivalent\text{ }wt.\text{ }of\text{ }metal+35.5}\]\[=\frac{2\times 94.8}{12+35.5}=4\] |
| \[\therefore \] Formula of compound \[=MC{{l}_{4}}\] |
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