JEE Main & Advanced Chemistry Some Basic Concepts of Chemistry / रसायन की कुछ मूलभूत अवधारणाएँ Question Bank Self Evaluation Test - Some Basic Concepts of Chemistry

  • question_answer
    1 mole of mixture of CO and \[C{{O}_{2}}\] requires exactly \[28g\text{ }KOH\] in solution for complete conversion of all the \[C{{O}_{2}}\] into\[{{K}_{2}}C{{O}_{3}}.\] How much amount more of KOH will be required for conversion into\[{{K}_{2}}C{{O}_{3}}.\] If one mole of mixture is completely oxidized to \[C{{O}_{2}}\]    

    A) 112g    

    B) 84g

    C) 56g                              

    D) 28g

    Correct Answer: B

    Solution :

    [b] \[CO+\frac{1}{2}{{O}_{2}}\to C{{O}_{2}};\]\[C{{O}_{2}}+2KOH\to {{K}_{2}}C{{O}_{3}}+{{H}_{2}}O\]
    Moles of \[KOH=\frac{28}{56}=0.50\]
    It corresponds to 0.25 mol of \[C{{O}_{2}}\]
    Hence mol of \[CO=1-0.25=0.75\]\[\equiv \] mole of \[C{{O}_{2}}\]formed
    Mol of KOH requred \[=2\times 0.75=1.5\]\[=1.5\times 56=84g\]


You need to login to perform this action.
You will be redirected in 3 sec spinner