A) \[8.30\times {{10}^{-23}}g\]
B) \[2.08\times {{10}^{-23}}g\]
C) \[5.53\times {{10}^{-23}}g\]
D) \[6.24\times {{10}^{-23}}g\]
Correct Answer: C
Solution :
| [c] The conditions given are standard conditions 224 mL has mass = 1 g; |
| 22400 mL will have mass = 100g. This is mol. wt of gas |
| \[6.023\times \text{1}{{0}^{23}}\]molecules have\[3\times 6.023\times {{10}^{23}}\], atoms since gas is triatomic |
| \[\therefore \]weight of one atom \[=\frac{100}{3\times 6.023\times {{10}^{23}}}=5.5\times {{10}^{-23}}g\] |
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