A) 3
B) 2
C) 4
D) 5
Correct Answer: B
Solution :
[b] Meq of oxalic acid in 16.68 ml = Meq of NaOH \[=25\times \frac{1}{25}\] Meq of oxalic acid in 250 ml \[=25\times \frac{1}{15}\times \frac{250}{16.68}=24.98\] \[\frac{1.575}{(90+18x)/2}\times 1000=24.98\] \[\therefore x=2\]You need to login to perform this action.
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