A) 35
B) 70
C) 30
D) 60
Correct Answer: C
Solution :
[c] \[5CO+{{I}_{2}}{{O}_{5}}\to 5C{{O}_{2}}+{{I}_{2}}\] |
Moles of\[{{I}_{2}}{{O}_{5}}=\frac{25.4}{254}\]\[=0.01=0.05\text{ }moles\text{ }of\text{ }CO\] |
Weight of \[CO=0.05\times 28=1.4\text{ }g;\] |
Weight of \[C{{O}_{2}}=2-1.4=0.6g\] |
Hence % of \[C{{O}_{2}}=\frac{0.6}{2}\times 100=30%\]% |
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