A) \[7.7\times {{10}^{23}}\]
B) \[~1.5\times {{10}^{23}}\]
C) \[4.3\times {{10}^{21}}\]
D) \[1.47\times {{10}^{22}}\]
Correct Answer: D
Solution :
| [d] Volume of gold foil \[=25\times 40\times 0.25\text{ }m{{m}^{3}}\] \[=250\times {{10}^{-3}}c{{m}^{3}}\] |
| Mass of gold foil \[=19.32\times 250\times {{10}^{-3}}g\]\[=4.83g\] |
| No. of gold atoms \[=\frac{4.83}{197}\times {{N}_{A}}\]\[=1.47\times {{10}^{22}}\] |
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