A) 7L
B) 6L
C) 5L
D) 10L
Correct Answer: C
Solution :
[c] Writing the equation of combustion of propane\[({{C}_{3}}{{H}_{8}})\], we get \[\underset{\begin{smallmatrix} 1\,vol \\ 1L \end{smallmatrix}}{\mathop{{{C}_{3}}{{H}_{8}}}}\,+\underset{\begin{smallmatrix} 5vol \\ 5L \end{smallmatrix}}{\mathop{5{{O}_{2}}}}\,\to 3C{{O}_{2}}+4{{H}_{2}}O\] From the above equation we find that we need 5 L of oxygen at NTP to completely burn 1 L of propane at N.T.P. If we change the conditions for both the gases from N.T.P. to same conditions of temperature and pressure. The same results are obtained, i.e. 5 L is the correct answer.You need to login to perform this action.
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