A) 0.6
B) 0.4
C) 0.5
D) 0.8
Correct Answer: B
Solution :
[b] \[{{C}_{2}}{{H}_{6}}+3.5{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}}+3{{H}_{2}}O;\] |
\[{{C}_{2}}{{H}_{4}}+3{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}}+2{{H}_{2}}O\] |
Let volume of ethane is x litre, \[22.4\times 4=3.5x+3\left( 28-x \right)\] |
\[\Rightarrow x=11.2\] litre at constant T and P, \[V\propto n\]: |
\[\Rightarrow \] Mole fraction of \[{{C}_{2}}{{H}_{6}}\]in mixture \[=\frac{11.2}{28}=0.4\] |
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