A) 25
B) 23
C) 51
D) 118
Correct Answer: D
Solution :
[d] Let x g of \[L{{i}_{2}}C{{O}_{3}}\] and \[\left( 1-x \right)g\] of \[{{M}_{2}}C{{O}_{3}}\] present in given mixture \[2\times \] Total moles of carbonates = moles of HCl and \[2\times \left( \frac{x}{74}+\frac{1-x}{2M+60} \right)=21.6\times 0.5\times {{10}^{-3}}\] \[x=0.20\] \[\therefore \frac{x}{74}=\frac{1-x}{2M+60}\] \[M=118\]You need to login to perform this action.
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