A) 5.9
B) 47.125
C) 94.25
D) 88.2
Correct Answer: C
Solution :
[c] Let mass of \[A{{g}_{2}}O=xg\] \[\begin{matrix} A{{g}_{2}}O & \xrightarrow{{}} & 2Ag & +\,\,\,\,\,\,\frac{1}{2}{{O}_{2}} \\ \overset{xg}{\mathop{232g}}\, & {} & {} & \frac{1}{2}\times 32=16g\,{{O}_{2}} \\ \end{matrix}\] \[\frac{16}{232}\times x=0.104\Rightarrow x=1.508g\] % of \[A{{g}_{2}}O=\frac{1.508}{1.6}\times 100=94.25\]%You need to login to perform this action.
You will be redirected in
3 sec