A) 2 times of \[{{H}_{2}}\] molecule
B) same as that of \[{{H}_{2}}\] molecule
C) 4 times that of hydrogen molecule
D) \[\frac{1}{2}\] that of \[{{H}_{2}}\] molecule
Correct Answer: B
Solution :
[b] \[K\overline{E}=\frac{3}{2}\frac{n}{{{N}_{o}}}RT\]. Average \[K\overline{E}\] is the same for all gaseous moleculesYou need to login to perform this action.
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