A) 18 mmHg
B) 20 mmHg
C) 22 mmHg
D) 24 mmHg.
Correct Answer: D
Solution :
[d] Volume of 0.0168 moles at STP \[=0.0168\times 22400=376.3mL.\] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] Or \[\frac{760\times 376.3}{273}=\frac{{{P}_{2}}\times 428}{298}\] or \[{{P}_{2}}=730mm\] Pressure of water \[=754-730=24\text{ }mm\text{ }Hg\]You need to login to perform this action.
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