A) 5.25 bar, 10 bar
B) 19.75 bar, 5.25 bar
C) 19.75 bar, 10 bar
D) 5.25 bar, 19.75 bar
Correct Answer: D
Solution :
[d] Number of moles of \[{{O}_{2}}\] \[=\frac{70.6}{32gmo{{l}^{-1}}}=2.21mole\] Number of moles of Ne \[=\frac{167.5g}{20gmo{{l}^{-1}}}=8.375mole\] Mole fraction of \[{{O}_{2}}\] \[=\frac{2.21}{2.21+8.375}=0.21\text{ }mole\] Mole fraction of \[Ne=1-0.21=0.79\] Partial pressure of a gas = Mole fraction x total pressure Partial pressure of \[{{O}_{2}}=0.21\times 25=5.25bar\] Partial pressure of \[Ne=0.79\times 25\] \[=19.75\text{ }bar\]You need to login to perform this action.
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