A) 80 cc
B) 88.9 cc
C) 66.7 cc
D) 100 cc
Correct Answer: B
Solution :
[b] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[\frac{P\times 100}{T}=\frac{1.5P\times {{V}_{2}}}{\frac{4T}{3}}\] \[{{V}_{2}}=88.9\,mL=88.9cc\]You need to login to perform this action.
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