A) 9.53 m
B) 95.3 m
C) 953 m
D) \[9.53\times {{10}^{4}}m\]
Correct Answer: D
Solution :
[d] \[\frac{3}{2}{{k}_{B}}T=mgh\] \[h=\frac{3}{2}\times \frac{1.38\times {{10}^{-23}}\times 300}{9.81\times 4\times 1.66\times {{10}^{-27}}}=9.53\times {{10}^{4}}m\]You need to login to perform this action.
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