A) \[1.247\times {{10}^{5}}L\]
B) \[1.66\times {{10}^{5}}L\]
C) \[1.66\times {{10}^{4}}L\]
D) None of these
Correct Answer: A
Solution :
[a] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] \[{{V}_{2}}=\frac{745\times 1.41\times {{10}^{4}}\times 225}{294\times 63.1}=1.274\times {{10}^{5}}L\]
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