A) 15
B) 10
C) 20
D) 25
Correct Answer: B
Solution :
[b] The volume of the balloon \[=\frac{4}{3}\pi {{r}^{3}}\] \[=\frac{4}{3}\times \frac{22}{7}\times {{\left( \frac{21}{2} \right)}^{3}}=4851\,mL\] Volume of the cylinder = 2820 mL Volume of \[{{H}_{2}}\] at NTP \[=\frac{20\times 2820\times 273}{300\times 1}mL=51324\,mL\] After filling the cylinder will have \[{{H}_{2}}\] equal to its volume = 2820 mL \[\therefore \] Volume of \[{{H}_{2}}\] for filling balloons \[=51324-2820=48504mL\] Hence no. of balloon to be filled \[=\frac{48504}{4851}\approx 10\]
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