A) 1, 2 and 3
B) 1 and 2 only
C) 2 and 3 only
D) 1 only
Correct Answer: D
Solution :
[d] Given, \[{{P}_{1}}=15atm,\,\,{{P}_{2}}=60atm\] \[{{V}_{1}}=76c{{m}^{3}},{{V}_{2}}=20.5c{{m}^{3}}.\] If the gas is an ideal gas, then according to Boyle's law, it must follow the equation, \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[{{P}_{1}}\times {{V}_{1}}=15\times 76=1140\] \[{{P}_{2}}\times {{V}_{2}}=60\times 20.5=1230\] \[\therefore {{P}_{1}}{{V}_{1}}\ne {{P}_{2}}{{V}_{2}}\] \[\therefore \] The gas behaves non-ideally. The given information is not sufficient to comment on other statements.
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