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NEET Chemistry States of Matter / पदार्थ की अवस्थाएँ - गैस एवं द्रव Question Bank Self Evaluation Test - States of Matter

  • question_answer
    The volume of 0.0168 mol of \[{{O}_{2}}\] obtained by decomposition of \[KCl{{O}_{3}}\] and collected by displacement of water is 428 mL at a pressure of 754 mm Hg at\[25{}^\circ C\]. The pressure of water vapour at \[25{}^\circ C\] is

    A) 18 mmHg         

    B) 20 mmHg

    C) 22 mmHg         

    D) 24 mmHg.

    Correct Answer: D

    Solution :

    [d] Volume of 0.0168 moles at STP \[=0.0168\times 22400=376.3mL.\] \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] Or \[\frac{760\times 376.3}{273}=\frac{{{P}_{2}}\times 428}{298}\] or \[{{P}_{2}}=730mm\] Pressure of water \[=754-730=24\text{ }mm\text{ }Hg\]


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