A) \[\frac{{{m}_{1}}}{u_{1}^{2}}=\frac{{{m}_{2}}}{u_{2}^{2}}\]
B) \[{{m}_{1}}{{u}_{1}}={{m}_{2}}{{u}_{2}}\]
C) \[\frac{{{m}_{1}}}{{{u}_{1}}}=\frac{{{m}_{2}}}{{{u}_{1}}}\]
D) \[{{m}_{1}}u_{1}^{2}={{m}_{2}}u_{2}^{2}\]
Correct Answer: D
Solution :
[d] \[{{U}_{1}}\propto \sqrt{\frac{1}{{{m}_{1}}}}\,and\,\,{{U}_{2}}\propto \sqrt{\frac{1}{{{m}_{2}}}}\] \[\therefore \frac{U_{1}^{2}}{U_{2}^{2}}=\frac{{{m}_{2}}}{{{m}_{1}}}\] \[\therefore {{m}_{1}}U_{1}^{2}={{m}_{2}}U_{2}^{2}\]
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