A) \[\bar{x}\]
B) \[na\bar{x}+nb\]
C) \[a\bar{x}\]
D) \[a\bar{x}+b\]
Correct Answer: D
Solution :
[d] Required mean \[=\frac{(a{{x}_{1}}+b)+(a{{x}_{2}}+b)+...+(a{{x}_{n}}+b)}{n}\] \[=\frac{a({{x}_{1}}+{{x}_{2}}+...+{{x}_{n}})+nb}{n}=a\bar{x}+b,\] \[\left( \because \frac{{{x}_{1}}+{{x}_{2}}+...+{{x}_{n}}}{n}=\bar{x} \right).\]
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