JEE Main & Advanced Mathematics Statistics Question Bank Self Evaluation Test - Statistics

  • question_answer
    If the mean of the numbers \[27+x,31+x,89+x,107+x,156+x\] is 82, then the mean of \[130+x\], \[126+x,\,\,68+x,\,\,50+x,\,\,1+x\]

    A) 75

    B) 157

    C) 82

    D) 80

    Correct Answer: A

    Solution :

    [a] Given \[82=\frac{(27+x)+(31+x)+(89+x)+(107+x)+(156+x)}{5}\]\[\Rightarrow 82\times 5=410+5x\Rightarrow 410-410=5x\Rightarrow x=0\] \[\therefore \] Required mean is, \[\bar{x}=\frac{130+x+126+x+68+x+50+x+1+x}{5}\] \[\bar{x}=\frac{375+5x}{5}=\frac{375+0}{5}=\frac{375}{5}=75\]


You need to login to perform this action.
You will be redirected in 3 sec spinner