A) 1
B) \[\frac{9}{4}\]
C) \[\frac{4}{9}\]
D) \[\frac{2}{3}\]
Correct Answer: A
Solution :
[a] \[\sigma _{x}^{2}=\frac{\sum{d_{i}^{2}}}{n}\] (Here deviations are taken from the mean). Since A and B both have 100 consecutive integers, therefore both have same standard deviation and hence the variance. \[\therefore \frac{{{V}_{A}}}{{{V}_{B}}}=1\] (As \[\sum{d_{i}^{2}}\] is same in both the cases)
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