JEE Main & Advanced Mathematics Statistics Question Bank Self Evaluation Test - Statistics

  • question_answer
    The mean and S.D. of the marks of 200 candidates were found to be 40 and 15 respectively. Later, it was discovered that a score of 40 was wrongly read as 50. The correct mean and S.D. respectively are

    A) \[14.98,39.95\]

    B) \[39.95,14.98\]

    C) \[39.95,224.5\]

    D) None of these

    Correct Answer: B

    Solution :

    [b] Corrected \[\Sigma x=40\times 200-50+40=7990\] \[\therefore \] Corrected \[\bar{x}=7990/200=39.95\] Incorrect \[\Sigma {{x}^{2}}=n[{{\sigma }^{2}}+{{\bar{x}}^{2}}]=200[{{15}^{2}}+{{40}^{2}}]\] \[=365000\] Corrected \[\Sigma {{x}^{2}}=365000-2500+1600=364100\] \[\therefore \] Corrected \[\sigma =\sqrt{\frac{364100}{200}-{{(39.95)}^{2}}}\] \[=\sqrt{(1820.5-1596)}=\sqrt{224.5}=14.98.\]


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