A) \[\frac{46}{3}\]
B) \[\frac{35}{4}\]
C) \[\frac{45}{4}\]
D) \[\frac{41}{4}\]
Correct Answer: C
Solution :
[c] Let total no. of obs \[=18\] Let mean of one group \[={{a}_{1}}=15\] And mean of other group \[={{a}_{2}}\] Given: Combined mean \[=\frac{40}{3}\] Now, combined mean \[=\frac{({{a}_{1}}\times 10)+({{a}_{2}}\times 5)}{18}\] \[\Rightarrow \frac{40}{3}=\frac{150+8{{a}_{2}}}{18}\Rightarrow {{a}_{2}}=\frac{45}{4}\]
You need to login to perform this action.
You will be redirected in
3 sec
