JEE Main & Advanced Mathematics Statistics Question Bank Self Evaluation Test - Statistics

  • question_answer
    If \[\sum\nolimits_{i=1}^{9}{({{x}_{i}}-5)=9}\] and \[\sum\nolimits_{i=1}^{9}{{{({{x}_{i}}-5)}^{2}}=45,}\] then the standard deviation of the 9 items \[{{x}_{1}},{{x}_{2}},...{{x}_{9}}\] is

    A) 9

    B) 4

    C) 3

    D) 2

    Correct Answer: D

    Solution :

    [d] Let \[\sum\limits_{i=1}^{9}{({{x}_{i}}-5)}=9\Rightarrow \sum\limits_{i=1}^{9}{{{x}_{i}}-\sum\limits_{i=1}^{9}{5=9}}\] \[\Rightarrow \sum\limits_{i=1}^{9}{{{x}_{i}}-(9\times 5)=9;}\] \[\sum{{{x}_{i}}-45=\Rightarrow \sum{{{x}_{i}}=54}}\] Similarly, \[\sum{x_{i}^{2}-10\times 54+25\times 9=45\Rightarrow \sum{x_{i}^{2}=360}}\] \[\Rightarrow \sigma =\sqrt{\frac{360}{9}-{{\left( \frac{54}{9} \right)}^{2}}}=\sqrt{\frac{324}{81}}=2\]


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