A) 12
B) 6.4
C) \[\sqrt{49.2}\]
D) 49.2
Correct Answer: D
Solution :
[d] The mean of the given items \[\overline{x}=\frac{3+7+10+18+22}{5}=12\] Hence, variance \[=\frac{1}{n}\sum{{{({{x}_{i}}-\bar{x})}^{2}}}\] \[=\frac{1}{5}\left\{ {{(3-12)}^{2}}+{{(7-12)}^{2}}+{{(10-12)}^{2}}+{{(18-12)}^{2}}+{{(22-12)}^{2}} \right\}\]\[=\frac{1}{5}\{81+25+4+36+100\}=\frac{246}{5}=49.2\]
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