A) \[{{x}_{1}}\]
B) \[{{x}_{51}}\]
C) \[\frac{{{x}_{1}}+{{x}_{2}}+...+{{x}_{101}}}{101}\]
D) \[{{x}_{50}}\]
Correct Answer: B
Solution :
[b] Mean deviation is minimum when it is considered about the item, equidistant from the beginning and end i.e. the median. In case median is \[\frac{101+1}{2}\]th i.e., 51st item i.e., \[{{x}_{51}}.\]
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