| Variate | Frequency |
| 10-20 20-30 30-40 40-50 50-60 60-70 70-80 | 12 30 ? 65 45 25 18 |
| Total | 229 |
A) 33.5
B) 35
C) 34
D) 26
Correct Answer: C
Solution :
[c] Median = 46 which lies in 40-50 class Median \[=l+h\frac{\left\{ \frac{n}{2}-{{C}_{f}} \right\}}{f}\] Where f= frequency of median - class \[{{C}_{f=}}\] Cumulative frequency of the class preceding the median class. \[\therefore 46=40+10\frac{\left[ \frac{229}{2}-(x+42) \right]}{65}\] Where x = frequency of class 30-40 \[\Rightarrow x=33.5=34.\]
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