A) \[x=y\ne z\]
B) \[x\ne y=z\]
C) \[x\ne y\ne z\]
D) \[x=y=z\]
Correct Answer: D
Solution :
[d] Given data \[3,,5,1,6,9,5,2,8,6\] and mean, median and mode are x, y, z respectively. Rearranging data \[1,2,3,5,5,5,6,6,8,9\] Mean \[=x\] \[=\frac{1+2+3+5+5+5+6+6+8+9}{10}=\frac{50}{10}=5\] Median \[=y=\frac{\frac{{{n}^{th}}}{2}term+{{\left( \frac{n}{2}+1 \right)}^{th}}term}{2}\] \[y=\frac{5+5}{2}=5\] Mode (z) = most frequently occurring value =5 Hence \[x=y=z.\]
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