A) 20.0
B) 10.1
C) 20.2
D) 10.0
Correct Answer: B
Solution :
[b] Mean \[=\frac{101+d(1+2+3+...+100)}{101}\] \[=1+\frac{d\times 100\times 101}{101\times 2}=1+50d\] \[\because \] Mean deviation from the mean = 255 \[\Rightarrow \frac{1}{101}[\left| 1-(1+50d) \right|+\left| (1+d)-(1+50d) \right|+\left| (1+2d)-(1+5d) \right|\]\[-(1+50d)|+...+\left| (1+100d)-(1+50d) \right|]=255\] \[\Rightarrow 2d[1+2+3+...+50]=101\times 255\] \[\Rightarrow 2d\times \frac{50\times 51}{2}=101\times 255\] \[\Rightarrow d=\frac{101\times 255}{50\times 51}=10.1\]
You need to login to perform this action.
You will be redirected in
3 sec
