question_answer

Two straight lines passing through the point \[A(3,2)\] cut the line \[2y=x+3\] and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

A) \[7x+y-21=0\]

B) \[x+7y+21=0\]

C) \[2x+y-8=0\]

D) \[x+2y+8=0\]

Correct Answer: A

Solution :

[a] \[\because \] Coordinate of Q are (3, 0) & it passes through PQ. \[\therefore \]Putting the values of \[(x=3)\And (y=0)\]is options we get. Equation of line \[PQ=7x+y-21=0\]