A) \[\sqrt{3}x+y=7\]
B) \[\sqrt{3}x-y=14\]
C) \[\sqrt{3}x+y+14=0\]
D) \[\sqrt{3}x+y-14=0\]
Correct Answer: D
Solution :
[d] Here p=7 and \[\alpha =30{}^\circ \] \[\therefore \] Equation of the required line is \[x\cos 30{}^\circ +y\sin 30{}^\circ =7\] or \[x\frac{\sqrt{3}}{2}+y\times \frac{1}{2}=7\] or \[\sqrt{3}x+y=14\]You need to login to perform this action.
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